Answer:
1. Even - B
2. Even - B
3. Odd - A
Step-by-step explanation:
Example 1: 7+7 = 14
7 is odd, 14 is even.
Example 2: 4 + 4 = 8
4 is even, and 8 is even.
Example 3: 4 + 5 = 9
4 is even, 5 is odd, 9 is odd.
The purple crayons take up 1/4 of the crayons in the jar. To get the answer:
140/4 = 35
The answers are 3/8 and 1/6.
There are 8 possible outcomes in the sample space for flipping 3 coins. Of those, 3 include two heads and 1 tail. This makes the probability 3/8.
Choosing a quarter for the first coin is 3/10, since there are 3 quarters out of 10 coins. After this, choosing a dime is given by 5/9, since there are 5 dimes out of 9 coins left:
3/10(5/9) = 15/90 = 1/6
Answer:
The sample size is 
Step-by-step explanation:
From the question we are told that
The margin of error is E = 1.5 seconds
The standard deviation is s = 4 seconds
Given that the confidence level is 97% then the level of significance is mathematically represented as
=> 
Generally from the normal distribution table the critical value of 
is
Generally the sample size is mathematically represented as
![n =[ \frac{Z_{\frac{\sigma }{2 } } * \sigma }{E} ]^2](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%20%5Cfrac%7BZ_%7B%5Cfrac%7B%5Csigma%20%7D%7B2%20%7D%20%7D%20%2A%20%20%5Csigma%20%7D%7BE%7D%20%5D%5E2)
=> ![n =[ \frac{2.17 * 4 }{1.5} ]^2](https://tex.z-dn.net/?f=n%20%20%3D%5B%20%20%5Cfrac%7B2.17%20%20%2A%204%20%7D%7B1.5%7D%20%5D%5E2)
=>
Given
26% = several simulations of a football player playing two games
Find the percentage of the simulations in each of the two games
2x = .26
2x = .26
---- -----
2 2
x = .13 * 100
x= 13
The answer is 13% of simulations would the football player be most likely to get a touchdown in each of the two games.
