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worty [1.4K]
3 years ago
5

Word phrase to represent 5x+2

Mathematics
2 answers:
notsponge [240]3 years ago
7 0
Five times the number x plus two
Makovka662 [10]3 years ago
3 0
Hey there!

Generally, variables can be referred to as "a number" or something similar since they have yet to be defined. Addition can be referred to as a number "more than" and multiplication can be said to be a number "times" or "multiplied by" another number. 

In this example, you can say that x is "a number" and that it is multiplied "times 5". The entire phrase could be "2 more than 5 times a number". 

Hope this helped you out! :-)
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Square root of -1 = 1. Math test
pantera1 [17]

Answer:

false. the sqrt of -1 = i

Step-by-step explanation:

6 0
2 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
The length and breadth of a rectangular shaped plot is 1215 m and 527 m respectively. Find its perimeter.
ss7ja [257]

Answer:

3484m

Step-by-step explanation:

Add 1215(2) and 527(2) together

4 0
2 years ago
Read 2 more answers
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
Visual learning, local learners ,physical learners and auditory learners how can you use this information to help you success ma
Lina20 [59]
All of these are different methods of learning math. Visually, you can see graphs, charts, and geometric figures to help you learn. I'm not sure what a 'local learner' is. Physical learners can learn better by holding geometric figures, drawing graphs, etc. Auditory learners may learn best by listening to a teacher's lecture.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)
4 0
2 years ago
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