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marusya05 [52]
2 years ago
14

3. Given the directed line segment AB, with endpoints A20, 6) and B(-16, 50), find the point Q

Mathematics
1 answer:
garri49 [273]2 years ago
8 0

The point Q that partitions the line segment is Q(2,28)

Given that the directed line segment AB, with endpoints A(20, 6) and B(-16, 50) and divide the segment into a 1:1 ratio.

A line segment is a part of a line bounded by two distinct endpoints and containing all the points of the line segment between its endpoints.

We will find the point Q by using the section formula that is

Q(x,y)=((mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n))

The given ratio is m:n=1:1 and the points (x₁,y₁)=(20,6) and (x₂,y₂)=(-16,50).

Firstly, we will find the point Q for x-axis, we get

Q(x)=(mx₂+nx₁)/(m+n)

Q(x)=(1×(-16)+1×20)/(1+1)

Q(x)=(-16+20)/2

Q(x)=4/2

Q(x)=2

Now, we will find the point Q for y-axis, we get

Q(y)=(my₂+ny₁)/(m+n)

Q(y)=(1×50+1×6)/(1+1)

Q(y)=(50+6)/2

Q(y)=56/2

Q(y)=28

The point Q that partitions the line segment is Q(x,y)=(2,28)

Hence, point Q partitions this segment into a 1:1 ratio with directed line segment AB, with endpoints A(20, 6) and B(-16, 50) is Q(2,28).

Learn more about the line segment from here brainly.com/question/9034900

#SPJ9

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1. Suppose that the average outstanding credit balance for young couples is $650 with a standard deviation of $420. In an SRS of
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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 650, \sigma = 420, n = 100, s = \frac{420}{\sqrt{100}} = 42

In an SRS of 100 couples, what is the probability that the mean outstanding credit balance exceeds $700?

This is 1 subtracted by the pvalue of Z when X = 700. So

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

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11.70% probability that the mean outstanding credit balance exceeds $700

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