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Mrac [35]
3 years ago
15

A stone is thrown upward from ground level. With what minimum speed should the stone be thrown so as to reach a height of 36 fee

t?
Mathematics
1 answer:
jeyben [28]3 years ago
5 0
15mph              ...................................................                                                                         
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The two-way table shows the number of students in a school who like reading and/or gardening.
lisov135 [29]

hello i just took the test the answer is 26

5 0
3 years ago
Consider the differential equation y'' − y' − 20y = 0. Verify that the functions e−4x and e5x form a fundamental set of solution
KIM [24]

Answer:

Therefore e^{-4x} and e^{5x} are fundamental solution of the given differential equation.

Therefore  e^{-4x} and e^{5x} are linearly independent, since W(e^{-4x},e^{5x})=9e^x\neq 0

The general solution of the differential equation is

y=c_1e^{-4x}+c_2e^{5x}

Step-by-step explanation:

Given differential equation is

y''-y'-20y =0

Here P(x)= -1, Q(x)= -20 and R(x)=0

Let trial solution be y=e^{mx}

Then, y'=me^{mx}   and   y''=m^2e^{mx}

\therefore m^2e^{mx}-m e^{mx}-20e^{mx}=0

\Rightarrow m^2-m-20=0

\Rightarrow m^2-5m+4m-20=0

\Rightarrow m(m-5)+4(m-5)=0

\Rightarrow (m-5)(m+4)=0

\Rightarrow m=-4,5

Therefore the complementary function is = c_1e^{-4x}+c_2e^{5x}

Therefore e^{-4x} and e^{5x} are fundamental solution of the given differential equation.

If y_1 and y_2 are the fundamental solution of differential equation, then

W(y_1,y_2)=\left|\begin{array}{cc}y_1&y_2\\y'_1&y'_2\end{array}\right|\neq 0

Then  y_1 and y_2 are linearly independent.

W(e^{-4x},e^{5x})=\left|\begin{array}{cc}e^{-4x}&e^{5x}\\-4e^{-4x}&5e^{5x}\end{array}\right|

                    =e^{-4x}.5e^{5x}-e^{5x}.(-4e^{-4x})

                    =5e^x+4e^x

                   =9e^x\neq 0

Therefore  e^{-4x} and e^{5x} are linearly independent, since W(e^{-4x},e^{5x})=9e^x\neq 0

Let the the particular solution of the differential equation is

y_p=v_1e^{-4x}+v_2e^{5x}

\therefore v_1=\int \frac{-y_2R(x)}{W(y_1,y_2)} dx

and

\therefore v_2=\int \frac{y_1R(x)}{W(y_1,y_2)} dx

Here y_1= e^{-4x}, y_2=e^{5x},W(e^{-4x},e^{5x})=9e^x ,and  R(x)=0

\therefore v_1=\int \frac{-e^{5x}.0}{9e^x}dx

       =0

and

\therefore v_2=\int \frac{e^{5x}.0}{9e^x}dx

       =0

The the P.I = 0

The general solution of the differential equation is

y=c_1e^{-4x}+c_2e^{5x}

7 0
3 years ago
What is an expression equivalent to 9(47) using the distributive property?
pickupchik [31]
The answer is 9(40+7)
7 0
3 years ago
Samual has a collection of toy cars his favorites are the 27 red ones which makes up 60% of his collection how many toy cars dos
vagabundo [1.1K]

Answer:

45

Step-by-step explanation:

Use khan acedaemy

5 0
2 years ago
Byron’s workout starts with a
Hatshy [7]

Answer:

An equation in point-slope form that represents Byron’s  distance from home, y, after  x hours is y=4x+2

Step-by-step explanation:

Speed of Byron = 4 miles / hour

Distance traveled in x hours = Speed \times time

Distance traveled in x hours = 4x

We are given that After half an hour of  running, he is 2 miles from home

So, Total distance = 4x+2

So, y = 4x+2

Hence an equation in point-slope form that represents Byron’s  distance from home, y, after  x hours is y=4x+2

7 0
3 years ago
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