Answer:
=25a6−36a4
Step-by-step explanation:
=(5a3+−6a2)(5a3+6a2)
=(5a3)(5a3)+(5a3)(6a2)+(−6a2)(5a3)+(−6a2)(6a2)
=25a6+30a5−30a5−36a4
=25a6−36a4
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
Read more on fundamental theorem of calculus;
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The data collected from the actual game experiment is:
Win: 8 times
Lose: 40 times
Total trials: 48 times
Therefore, the probability that you will win when you play this game is:
WIN = 8/48
= 1/6 or 0.1667 = 16.67% chance of winning
LOSE = 40/48
= 5/6 or 0.8333 = 83.33% chance of losing.
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X= -2x -15y -45 maybe i’m kinda stupid