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3 years ago

Why do you think ionic bonds are generally weaker than covalent bonds?

1 answer:

5 0

<span> The short answer is that they are not always weaker in fact. Some ionic compounds have very strong bonds, while some covalent bonds are quite weak. Usually however, it is easier to break an ionic bond than a covalent one. What determines the actual strength of a bond is quite complex, but let me try to explain the basic principles. this is the best answer i can come up with</span>

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a spotted lizard runs at 3m/s at top speed. a girl wants to catch the lizard to keep as a pet. where should the girl place her c

Ann [662]

The acceleration due to earth's gravity is -9.8 m/s [dn] I thought... I'm assuming this is a projectile motion question asking for the range.

Break each kinematic quantity into their x and y components.

x y

v₁ = 3 m/s 0

v₂ = 3 m/s ?

Δd = ? -1.5

Δt = ? ?

a = 0 -10 m/s²

So the variable we are trying to find is Δdx (x component of displacement). We need to use a kinematic equation to do so. However, we obviously don't have enough given to find Δdx. This means we need to find something first, something we can use. How about Δt? Δt can be applied to both the x and y components. We have enough information in the y component list to find Δt. We can use this formula and solve for Δt.

Δdy = v₁y ( Δt ) + 1/2 ( ay ) ( Δt )²

Δdy = 1/2 ( ay ) ( Δt )² <- the first term cancels out since v₁y = 0.

2Δdy = ay ( Δt )²

2Δdy / ay = ( Δt )²

√ 2Δdy / ay = Δt

√ 2(-1.5 m/s) / -9.8 m/s² = Δt

√ -3.0 m/s / -9.8 m/s² = Δt

√ 0.3<u>0</u>6122449 s² = Δt

0.5<u>5</u>32833352 s = Δt

Now, we can use this newly found quantity to solve for Δdx using the x component values using the appropriate kinematic equation.

Δdx = ( v₁x + v₂x / 2) ( Δt )

Δdx = ( ( 3.0 m/s + 3.0 m/s ) / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 6.0 m/s / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 3.0 m / s )( 0.5<u>5</u>32833352 s )

Δdx = 1.<u>6</u>59850006 m

Therefore, the girl should place her cage 1.7 m away from the platform to catch the lizard.

This solution assumes that the acceleration due to gravity is -10 m/s² [dn] and not -9.8 m/s² [dn]. If you need -9.8 m/s² [dn], then just substitute it into my solution. This was a pain to type lol

6 0

4 years ago

Compare mass and mass number.

devlian [24]

Answer:

Atomic mass is the weighted average mass of an atom of an element based on the relative natural abundance of that element's isotopes. The mass number is a count of the total number of protons and neutrons in an atom's nucleus.

7 0

3 years ago

ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. You travel 20.0 mph f

timurjin [86]

The actual answer is 165 miles, but using significant figure rules the answer is 200. This is because the sig fig rules are as follows ...
<span>1. Non-zero digits are always significant.
2. Any zeros between two significant digits are significant.
<span>3. A final zero or trailing zeros in the decimal portion ONLY are significant.
</span></span>
So the zeroes in a number like 20 or 23,000 are NOT significant. When you add numbers you must find the addend with the lowest amount of significant figures and round the answer to that. In this case most of the addends only have one sig fig, so you round 165 to 200 to make it only have one sig fig.

5 0

4 years ago

Read 2 more answers

Yo someone help me on dis jawnt rq plzzz!

Phantasy [73]

Answer:

the answer is 45.6 kg = 45600 g

7 0

3 years ago

A car speeds past a stationary police officer while traveling 135 km/h. the officer immediately begins pursuit at a constant acc

kykrilka [37]

(a) The time it takes for the police officer to catch up to the speeding car is determined as 0.31 s.

(b) The speed of the police officer at the time he catches up to the driver is 136.8 km/h.

<h3>Time of motion of the police</h3>

The time taken for the police to catch up with the driver is calculated as follows;

v = at

where;

a is acceleration = 11.8 km/h/s, = 3.278 m/s²
v is velocity = 135 km/h = 37.5 m/s

t = v/a

t = 37.5/3.278

t = 11.4 seconds

(v1 - v2)t = ¹/₂at² --- (1)

(v1 - v2)t = v1²/2a --- (2)

From (1):

(v1 - 37.5)t = ¹/₂(3.278)t²

(v1 - 37.5)t = 1.639t²

v1 - 37.5 = 1.639t

v1 = 1.639t + 37.5 -----(3)

From (2):

(v1 - 37.5)t = v1²/(2 x 3.278)

(v1 - 37.5)t = 0.153 ----- (4)

solve 3 and 4;

(1.639t + 37.5 - 37.5)t = 0.153

1.639t² = 0.153

t² = 0.0933

t = 0.31 s

<h3>Speed of the police officer</h3>

v1 = 1.639(0.31) + 37.5 = 38 m/s = 136.8 km/h

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

4 0

2 years ago