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lbvjy [14]
3 years ago
14

Calculate the resistance in a circuit with a 16 volt battery and 4 amps of current.

Physics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

4 ohms

Explanation:

16v=Ω(4A)

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I need help this is due today GIVING BRAINLIEST IM DESPERATE!
Nitella [24]

Answer:

1: is A

2: is C

Explanation:

1: because all other option would imply that the truck was not moved from from its previous position due to the lack of work / force exerted by the car

2: this is because the less dense ball will have less opposing force action on it causing it to move / accelerate / go at a faster speed

3 0
3 years ago
Two horizontal curves on a bobsled run are banked at the same angle, but one has twice the radius of the other. The safe speed (
iren [92.7K]

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}................ii

form i and ii we can write

v^2= \frac{1}{2} u^2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

4 0
4 years ago
Look at the graph below.
Fiesta28 [93]

Answer:

I'm pretty sure its C

Explanation:

4 0
3 years ago
Betty weighs 400 N and she is sitting on a playground swing seat that hangs 0.21 m above the ground. Tom pulls the swing back an
disa [49]

Answer:

4.15 m/s

Explanation:

As the total energy must be conserved (neglecting air resistance) the change in gravitational potential energy, must be equal to the change in kinetic energy:

ΔE = ΔK + ΔU =0

If we take as a zero reference level for the gravitational potential energy, the height of the swing seat above the ground, (which is equal to 0.21 m), we can find the initial gravitational energy, considering the height of the point where the seat is released, regarding this point:

h₀ = 1.09 m -0.21 m = 0.88 m

⇒ U₀ = m*g*h₀ = 400 N*0.88 m = 352 J

As Uf = 0, ΔU = Uf -U₀ = -352 J

As the swing starts from rest, K₀=0, so we can say:

ΔK = Kf = \frac{1}{2} *m*vf^{2}  (1)

As ΔK = -ΔU ⇒ ΔK = 352 J (2)

From (1) and (2) we can solve for vf, as follows:

vf = \sqrt{\frac{2*352J}{40.8kg}} = 4.15 m/s

So, when the swing passes through its lowest position, Betty moves at 4.15 m/s.

5 0
4 years ago
A magnesium surface has a work function of 2.65 eV. Electromagnetic waves with a wavelength of 280 nm strike the surface and eje
Neko [114]

Answer:

Explanation:

Energy of radiation in eV = 1237.5/280 = 4.42 eV.

Work function = 2.65 eV.

Maximum kinetic energy = 4.42 - 2.65 = 1.77 eV.

8 0
4 years ago
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