If there was zero change in earths eccentricity how might that affect the possibility of an ice age?

Can a person be composite

Paha777 [63]

Answer:

yes

Explanation:

7 0

3 years ago

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4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)

docker41 [41]

Answer and Explanation:

A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).

The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental) gro+gro ro+ro x grogro roro

Gametes) gro+ro+ gro ro

gro+ro gro ro

gro ro+ gro ro

gro ro gro ro

Punnet square)

gro+ro+ gro+ro gro ro+ gro ro

gro ro gro+gro ro+ro gro+gro roro grogro ro+ro grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

Note: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are gro+ro+ and gro ro, while the parental gametes are gro+ro and gro ro+.

So, the genotype, in linked gene format, of the double heterozygote individual in the F1 is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The genetic distance between genes, is 0.011 x 100= 1.1 MU.

Genetic Linkage Map:

Parental Phenotypes)

-----gro+------ro---- -----gro------ro+----

----- gro ------ro---- ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+---- -----gro------ro----

----- gro ------ ro---- -----gro------ro----

If the genes were unlinked and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro

4/16 = 1/4 gro+gro roro

4/16 = 1/4 grogro ro+ro

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.

7 0

3 years ago

What are the structures and organelles of protozoans?

dangina [55]

The ciliates have both a micronucleus and macronucleus, which appear quite homogeneous in composition. The organelles of protozoa have functions similar to the organs of higher animals. The plasma membrane enclosing the cytoplasm also covers the projecting locomotory structures such as pseudopodia, cilia, and flagella.

5 0

2 years ago

4After completing their study of the carbon cycle, three students wrote statements making claims related to this topic. Read eac

mario62 [17]

Answer:

Incorrects:

Claim 1: When forests are cleared, we take away an opportunity to remove carbon from the atmosphere.

Claim 2: Carbon moves through biological systems and returns to the atmosphere through photosynthesis.

Claim 3: The amount of carbon involved in rapid cycling is much less than 1 percent of the total amount of carbon on Earth.

Explanation:

The carbon contained in forest products makes a small and manageable contribution to the global carbon balance. Globally, the net effect on atmospheric concentration is negligible, unless the rate of decomposition in geographically displaced product stocks is different from that in the forest ecosystem from which it was removed. However, controlling these rates through proper management can lead to some degree of mitigation of increases in atmospheric CO2.
During the carbon cycle, animals and plants release carbon dioxide into the atmosphere through cellular respiration, and plants capture carbon dioxide through photosynthesis.
The amount of carbon involved in rapid cycling it is the largest since it includes the carbon exchange between living beings, and is intertwined with the carbon cycle through long-term geological processes

8 0

3 years ago

Best answer gets brainiest

belka [17]

Answer: Warm air rises, creating a low pressure zone; cool air sinks, creating a high pressure zone. Air that moves horizontally between high and low pressure zones makes wind. The greater the pressure difference between the pressure zones the faster the wind moves. Convection in the atmosphere creates the planet's weather.

Hope this helps... Stay safe and have a great weekend!!! :D

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3 0

3 years ago