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Alja [10]
4 years ago
5

A 15 ft. Ladder is placed against a building so that the distance from the top of the ladder to the ground is 10 ft. Find the di

stance (to the nearest tenth) from the bottom of the ladder to the building
Mathematics
1 answer:
kipiarov [429]4 years ago
3 0

Answer:

  11.2 ft

Step-by-step explanation:

Assuming the building meets the ground at right angles, the right triangle formed has side length 10 ft and hypotenuse 15 ft. Then the other side length (d) is given by the Pythagorean theorem as ...

  d² + 10² = 15²

  d² = 225 -100 = 125

  d = √125 = 5√5 ≈ 11.2 . . . feet

The bottom of the ladder is about 11.2 feet from the building

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3 years ago
What value of n makes each statement true, pls include work
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1. n=2

2. n=12

3. n=2

Step-by-step explanation:

1

12xy³/4xⁿy=3y²/x

12x²y³=12y³xⁿ (cross multiplied)

x²=xⁿ (cancelled out (12y³))

2=n

2

(-3a/2b⁴)³=-27a³/8bⁿ

-27a³/8b¹²=-27a³/8bⁿ (cubed left side)

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bⁿ=b¹² (cancelled out (-216a³))

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3

(xy⁶/x⁵yⁿ)²=y⁸/x⁸

x²y¹²/x¹⁰y²ⁿ=y⁸/x⁸ (squared left side)

x²y¹²/x¹⁰y²yⁿ=y⁸/x⁸

y¹⁰/x⁸yⁿ=y⁸/x⁸ (simplified)

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6 0
3 years ago
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Step-by-step explanation:

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Third term : a_3= 19=12+7

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Explicit rule for Arithmetic sequence :

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Put a_1=5 and d=7

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The required  explicit rule that can be used to find the number of homes sold in the nth month of the year : a_n=7n-2

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