4. You have five people who are your friends on a certain social network. You are related to two of the people, but you do not r
ecall who of the five people are your relatives.
You are going to invite two of the five people to a special meeting. If you randomly select two of the five people to invite, explain how you would derive the probability of inviting your
relatives to this meeting.
You are going to invite two of the five people to a special meeting. If you randomly select two of the five people to invite, explain how you would derive the probability of inviting your
relatives to this meeting.
1 answer:
Answer:
the probability of inviting both relatives to the meeting = 1/10
Step-by-step explanation:
There are total two invitations that I will send, hence two selections.
For the first selection, I have 5 people total and two of them relatives.
Hence, the probability of inviting relative in first choice is 2/5.
Now assuming that we have invited one relative out of 5 people,
we are left with only 4 people out of which one is relative.
So, probability of inviting relative in second choice is 1/4.
So the probability of inviting both the relatives is (2/5)*(1/4) = 1/10
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Melanie: 15 years old
Kevin: 5 years old
Assume Kevin's present age is x.
That means that 3 years ago, his age would be x - 3.
Melanie's age would be 6(x - 3).
Same thing for 5 years into the future:
Kevin's age would be x + 5.
Melanie's age would be 2(x + 5).
The two equations we have here are:
By subtracting both equations, we are simplified to:
8 = -4x + 28
By solving the equation, we get x = 5.
That means that Kevin's current age is 5 years old.
Melanie's age could be calculated by substituting Kevins'.
6(x - 3) --> 6(5 - 3) --> 12
Since that was 3 years ago, you need to add 3 to 12 to get her current age.
12 + 3 = 15
Melanie's current age is 15 years old.