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Molodets [167]
3 years ago
12

Mary is selling chocolate bars to raise money. She earns $3 for each solid milk chocolate bar sold and $4 for each caramel-fille

d bar sold. If m represents the number of milk chocolate bars sold, and c represents the number of caramel bars sold, which of the following expressions represents the amount of money that Mary has raised? Question 6 options: A) 3m – 4c B) m∕3 + i∕4 C) 12mc D) 3m + 4c
Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

3m + 4c

Step-by-step explanation:

Whenever a word problem says the word earn that means the slope, also known as the rate of change, will be positive. Knowing this you can determine that both the caramel and milk chocolate slopes will be positive. After figuring all that out the only thing left to do is to make the equation. You know you have two slopes, and each slope needs a variable, so you will have to look back at the question. It is given that m represents the milk chocolate and c represents the caramel. Now all you have to do is make the slope the coefficient to the corresponding variable. The milk chocolates are 3 dollars, so the 3 goes in front of the m and the caramel chocolates are 4 dollars, so teh 4 goes in front of the 4. Since both slopes are positive no negatives or minus signs will be used in the equation. Knowing all this information you can now create the expression 3m + 4c.

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Answer:

yes yes no no

Step-by-step explanation:

use the Pythagorean theorem. sub a^2+b^2=c^2.

c is the largest number, and you can plug the 2 other values into a and b.

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What is the slope of the line that contains the points A(−3,12) and B(2,−4)?
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3 years ago
Read 2 more answers
A total of $4000 is invested: part at 8% and the remainder at 14%. How much is invested at each rate if the annual interest is $
skelet666 [1.2K]

Answer:

$2000 is invested at 8%

$2000 is invested at 14%

Step-by-step explanation:

A total of $4000 is invested part at 8% and the remainder at 14%

Annual interest is $440.

Simple interest formula;

I = P × R × T

Where I is the interest, P is the principal, R is the rate and T is the time.

P = $4000

R = 8% and 14%

T = 1 year

I = $440

Let's say $a is invested at 8% and;

$b is invested at 14%

Then,

($a × \frac{8}{100} × 1 ) + ($b × \frac{14}{100} × 1) = $440

and

$a + $b = $4000

This forms a simultaneous equation;

0.08a + 0.14b = 440 ... (i)

a + b = 4000 ... (ii)

Multiplying (i) by 1 and (ii) by 0.08  we get;

0.08a + 0.14b = 440 ... (i)

0.08a + 0.08b = 320 ... (ii)

Subtracting (i) - (ii) we get;

0 + 0.06b = 120

0.06b = 120

b = 120 ÷ 0.06 = 2000

So amount invested at 14% ($b) = $2000 and,

The amount invested at 8% ($a) = $4000 - $2000 = $2000

7 0
3 years ago
Juliette spends $6.12 at the store Morgan spends 3 times as much as Juliette Jonah spends $4.29 more than Morgan how much money
lions [1.4K]
6.12 x 3=18.36
18.36+4.29=22.65
convert to money = $22.65

7 0
3 years ago
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