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netineya [11]
3 years ago
7

What doexs this equal: 3ab-9ab+7ab

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

I think that it equals 1ab. Because 3ab - 9ab= -6ab + 7ab= 1ab



jasenka [17]3 years ago
7 0

So, this question tests wether or not you know how to combing "like terms".


Like terms are terms (thing inbetween +or-) that have the same variables.

Since all three terms contain "ab" we can add and subtract them.


So, 3ab-9ab = -6ab

-6ab+7ab=1ab


1ab is the correct answers

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mr Goodwill [35]

Answer:

negative infinite, negative 72

Step-by-step explanation:

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Write each expression without the absolute value symbol |3x+12|
klasskru [66]

Answer:

Step-by-step explanation:

|3x+12|

one is as it is                                     one is the negative value of it

3x + 12                                                   - (3x + 12)

                                                               - 3x - 12

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3 0
3 years ago
4 questions! Write an equation in slope-intercept form for each of the following:
AysviL [449]
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3 0
2 years ago
An airplane is flying overhead at a constant elevation of 405 ft. A person is viewing the plane from a position 3040 ft from the
Gnoma [55]

Answer:

δL/δt = 634,38 ft/s

Step-by-step explanation:

A right triangle is shaped by  ( y = distance between aircraft and ground which is constant and equal to  405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f   and the line between the aircraft and the person. Then we can use Pythagoras theorem and write

L ( distance between aircraft and person )

L²  =  x²  +  y²      or    L²  =  x²  + (405)²

Taken partial derivatives with respect to t we get:

2*L*δL/δt    =  2*x*δx/t + 0

Then      L*δL/δt = x*δx/dt

At the moment of the aircraft passing over the tower

x = 3040 ft       δx/δt = 640 ft/s   and L = √ ( 3040)² + (405)²

So   L  = √9241600  + 164025        L = √9405625   L ≈3066,9 ft

Then:

δL/δt = 3040*640/ 3066,9         units   [ ft * ft/s / ft ]   ft/s

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5 0
3 years ago
The temperature inside a certain industrial machine at time t seconds after startup, for 0 < t < 10, is given by h(t) = 42
frutty [35]

Answer:

t= \frac{125}{38} s

Step-by-step explanation:

We are given the temperature inside the machine from startup until 10 seconds later, the formula is:

h(t)= 42 \cdot t +1 - 4\cdot t +2  (degrees \, C)

We want to know at what time t the temperature inside the machine will be equal to 128 °C.

So we set:

h(t)=128

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Now, we rearrange the equation to keep terms with t on the left hand side and terms without t on the right hand side

42\cdot t-4\cdot t=128-1-2

and we simplify:

(42-4)\cdot t= 128-2-1= 125

38 \cdot t = 125

now it's easy to solve for t:

t=\frac{125}{38}

And thus we arrive to the solution.

5 0
3 years ago
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