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romanna [79]
3 years ago
7

The temperature inside a certain industrial machine at time t seconds after startup, for 0 < t < 10, is given by h(t) = 42

t + 1 – 4t + 2 degrees Celsius. How many seconds after startup is the temperature inside the machine equal to 128 degrees Celsius?
Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

t= \frac{125}{38} s

Step-by-step explanation:

We are given the temperature inside the machine from startup until 10 seconds later, the formula is:

h(t)= 42 \cdot t +1 - 4\cdot t +2  (degrees \, C)

We want to know at what time t the temperature inside the machine will be equal to 128 °C.

So we set:

h(t)=128

42\cdot t+1-4\cdot t+2=128

Now, we rearrange the equation to keep terms with t on the left hand side and terms without t on the right hand side

42\cdot t-4\cdot t=128-1-2

and we simplify:

(42-4)\cdot t= 128-2-1= 125

38 \cdot t = 125

now it's easy to solve for t:

t=\frac{125}{38}

And thus we arrive to the solution.

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1 year ago
What is the value of n in the equation-1/2(2n+4)+6=9+4(2n+1)
Bumek [7]

Answer:

Answer is -5/7 or -0.714284

Step-by-step explanation:

So we are going to have to remember how to use the pemdas, or the steps of how to solve these types of equations. We are going to dive straight into the parenthesis and distribute the 1/2 to both 2n and 4. We would get

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Then let's do the same to the 4 and distribute it to the 2n and 1.

n+2+6=9+8n+4

We need to add all common variables on the sides before anything else. So lets add 2 and 6 on the left side.

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Then we need to add 4 and 9 on the right side.

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We need to subtract 8 from the left and right side to get rid of 8.

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3 0
3 years ago
A recipe calls for 5/6 cup of flour Dixie wants to make 3/5 dixie currently has 3/4 cups of flour does she have enough to make t
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Answer:

No

Step-by-step explanation:

5/6 - 3/4

20 - 12 = 8

_____ __

24 24

Cancelling out, we have

=>1/3

She does not have enough cup of flour. She needs 1/3 more to be able to make the recipe.

<em>Hope</em><em> </em><em>it helps</em><em> </em>

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