What is your question exactly?
Slope intercept form
y=mx+b
m=slope
b=yintercept
slope for the line passing through the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(2,-2) and (2,-3)
slope=(-3-(-2))/(2-2)=(-1)/0=undefined
y=undefinedx
this means that the equation is x=something
we see
(x,y)
(2,-2)
(2,-3)
x=2 is the equation
we cannot write it in slope intercept form
Answer:
The area of triangle is 
Step-by-step explanation:
Let
B -----> the measure of the vertex angle of the isosceles triangle ABC
a and c -----> the two congruent sides of the isosceles triangle ABC
we know that
The area of a triangle applying the law of sines is equal to

we have


substitute in the formula


C+a=166
a=166-c
5.3c+9.2a=1254.2
5.3c+9.2(166-c)=1254.2
5.3c+1527.2-9.2c=1254.2
5.3c-9.2c=1254.2-1527.2
-3.9c=-273
c=-273/-3.9
c=70
Hope this helps!
Answer:
5x -7y = 21
Step-by-step explanation:
A sketch can convince you that BC is a transversal perpendicular to parallel lines AB and CD. The question asks for an equation for CD, so we just need to write the equation of a line through D that is parallel to AB.
One way to do this is to equate the slopes of the parallel lines:
∆y/∆x for AB = ∆y/∆x for CD
(y2 -y1)/(x2 -x1) = (y -2)/(x -7) . . . . . . where (x1, y1) = A; (x2, y2) = B; (7, 2) = D
(4 -(-1))/(1 -(-6)) = (y -2)/(x -7)
5(x -7) = 7(y -2) . . . . . . . . . . . . . cross multiply
5x -7y = 21 . . . . . . . . . . . . . . . . add 35 -7y, simplify
_____
Note that the graph shows the line CD is named "b", and its equation is shown at upper left. Multiplying that equation by -1 gives the one shown here.