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mart [117]
3 years ago
12

A major stadium has 45,000 seats. If baseball fans have bought 5/8 of the seats for the next game, how many seats are available?

3. Draw a picture or a chart that shows the information and the question
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0
Given:
45,000 seats
5/8 of the seats were bought for the next game.

To get the exact number of seats, we need to multiply the total number of seats by the fraction bought.

45,000 * 5/8 = (45,000 * 5) / 8 = 225,000 / 8 = 28,125 seats

5/8 of the total seats is 28,125 seats which are all unavailable.

8/8 - 5/8 = 8-5/8 = 3/8 is the fraction of the seats available.

45,000 - 28,125 = 16,875 seats available.

45,000 * 3/8 = (45,000 * 3) / 8 = 135,000 / 8 = 16,875
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Step-by-step explanation:

So for example 5/25 is a perfect square but 2/5 wouldn't be a perfect square.

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4 years ago
An Xbox one that costs $525 is discounted 15% for a sale. What is the new discounted price of the xbox one
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Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

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brainly.com/question/15161224

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7 0
2 years ago
Help it's due tomorrow!!!!
zepelin [54]
8a^2 + 3a^2

11a^2 

since both have a^2 you only have to add the coefficients 
5 0
3 years ago
The miller wants to bake a loaf of bread,but he didnt have any flour. He decided to grind just enough for eight loaves. If it ta
anyanavicka [17]
The miller needs 1-3/4 kg (or  1.75 kg) for two loaves.
Therefore the amount of flour needed for 1 loaf is
1.75/2 = 0.875 kg per loaf.

For 8 loaves, the amount of flour needed is 
8*0.875 = 7 kg

Answer: 7 kg of flour is needed for 8 loaves.
6 0
4 years ago
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