All categories

3 years ago

What is the negation of the follwoing conditional statement? "If a parallelogram has four congruent sides then it is a rhombus".

Mathematics

2 answers:

garri49 [273]3 years ago

8 0

<h2>Answer:</h2>

The negation of the given statement is:

A parallelogram has four congruent sides and it is not a rhombus.

<h2>Step-by-step explanation:</h2>

We know that for any conditional statement of the type:

If p then q

where p is the hypotheses and q is the conclusion then the negation of the statement is given by:

p and not q.

Here we are given a conditional statement as:

"If a parallelogram has four congruent sides then it is a rhombus".

Hence, the negation of this statement will be:

A parallelogram has four congruent sides and it is not a rhombus.

Kamila [148]3 years ago

3 0

Negation...means put " not " in both the hypothesis and conclusion

if a parallelogram DOES NOT have 4 congruent sides, then it is NOT a rhombus.

You might be interested in

Select the correct choice and fill in the answer box

Anvisha [2.4K]

To begin with, let us look at a few definitions that will help

A relation is a function if each x-value is paired with exactly one y-value. A vertical line test on a graph can be used to determine whether a relation is a function.

If we use a graph to check, we will have

We can see that there is no overlapping of coordinates. The table satisfies the vertical line test.

Hence, it is a function

The domain and range of function is the set of all possible inputs and outputs of a function respectively. The domain and range of a function y = f(x) is given as domain= {x ,x∈R }, range= {f(x), x∈Domain}.

The domain of the function, D is given by

$D=\mleft\lbrace-1,0,1,2,3\mright\rbrace$

The range, R is given by

$R=\mleft\lbrace-6,-1,2,5,8\mright\rbrace$

8 0

1 year ago

Please answer asap no work needed :)

Marat540 [252]

Answer:

2x+12 simplified is x+4

3 0

3 years ago

Read 2 more answers

Heyyy ummm... help??

atroni [7]

The statements true for the given function are:

$f(0) = \frac{3}{2}$
$f(4) = \frac{7}{2}$

I tried them all and these two were correct, their solutions are as follows:

= f(x) = 1/2x + 3/2

= f(0) = 1/2 × 0 + 3/2

= f(0) = 0 + 3/2

= f(0) = 3/2

= f(x) = 1/2x + 3/2

= f(4) = 1/2 × 4 + 3/2

= f(4) = 2 + 3/2

= f(4) = 4+3/2

= f(4) = 7/2

So, that's how these two are correct.

7 0

3 years ago

Read 2 more answers

Which is the graph of y = cos(x) + 3?

Elena-2011 [213]

Hi, I hope this helps !

5 0

2 years ago

Read 2 more answers

I need help with these two problems please

Debora [2.8K]

Problem 2

Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.

Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.

Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.

======================================================

Problem 3

The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.

The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.

If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF

Then we can say,

GH = GN + NH

GH = EF + EF

GH = 2*EF

7 0

3 years ago