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shusha [124]
2 years ago
13

Which one of these is not a step used when constructing an inscribed equilateral triangle using technology?

Mathematics
1 answer:
dusya [7]2 years ago
6 0
The third one duhhh, Ik this stuff
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Need help ...,,.....,,........
Hatshy [7]

Answer:

i’m pretty sure that it’s 50. i haven’t done this in a awhile though. but pretty positive it’s 50

Step-by-step explanation: :)

6 0
3 years ago
This section of a concrete skateboard ramp has the shape of a triangular prism. Find the volume of the triangular prism. Find th
NISA [10]

Answer:

The volume of the triangular prism: 59.2 ft^{3}

The value of the concrete used is: 16*4 = $64

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo

My answer:

As we know that, the formula to find out the volume of the triangular prism is:

V = \frac{1}{2} a*b*h when h is the height and a&b are the length of the two square edges. So we have:

  • V = \frac{1}{2}*4*4*7.4 = 59.2 ft^{3}

To find the concrete used in the ramp if the cost of concrete is $ 4.00 per cubic foot, we need to know the area of the ramp, which is:

S = 4*4 = 16 ft^{2}

Hence, the value of the concrete used is: 16*4 = $64

8 0
3 years ago
Read 2 more answers
This is the graph they gave me to plot it on
Flura [38]

check the picture below.

5 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
PLEASE HELP!! Will Mark brainliest!!
jeka57 [31]

Answer:

13 level

Step-by-step explanation:

143/55 = 2.6

5 x 2.6 = 13

8 0
3 years ago
Read 2 more answers
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