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Rufina [12.5K]
4 years ago
12

According to selye, some people may develop illnesses such as high blood pressure or a weakened immune system during the _______

_ stage of the general adaptation syndrome. alarm collapse exhaustion resistance
Biology
1 answer:
Sever21 [200]4 years ago
6 0
I believe the answer for the above question is exhaustion stage.
Hans selye, described three predictable stages the body uses to respond to stressors, called general adaptation syndrome (GAS). The first stage is alarm stage, which provides burst energy, then the resistance stage where the body attempts to resist or adapt to the stressor, and finally the exhaustion stage. During the resistance stage, the body uses its resources of flight off the stressor. It is not until the next stage, exhaustion, that bodily resources are so depleted that stress-related diseases can develop. 
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3 years ago
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In red shift, the wavelengths of light become:
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3 years ago
1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently
maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0
3 years ago
Read 2 more answers
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