Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
Answer:
beesechurger
Step-by-step explanation:
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Answer:
bonjour voilà la réponse 4.55
Geometric because the common factor is -3. each time it’s being multiplied by negative 3.
ANSWER/// GEOMETRIC
