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3 years ago

Hurry please What is the value of 12 Superscript 0?

Mathematics

2 answers:

allochka39001 [22]3 years ago

8 0

Answer:

The answer you are looking for is 1

Step-by-step explanation:

Any number raised to the power of one equals the number itself. Any number raised to the power of zero, except zero, equals one. This multiplication rule tells us that we can simply add the exponents when multiplying two powers with the same base.

Please tell me if it is correct using the ratings or thanks

Vera_Pavlovna [14]3 years ago

5 0

Answer:

the answer is 1

Step-by-step explanation:

anything to the 0th power is 1

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-3r + 18 = 15r please help!!

Luba_88 [7]

Answer:

r = 1

Step-by-step explanation:

Step 1: Write equation

-3r + 18 = 15r

Step 2: Solve for <em>r</em>

Add 3r to both sides: 18 = 18r
Divide both sides by 18: 1 = r
Rewrite: r = 1

Step 3: Check

<em>Plug in r to verify it's a solution.</em>

-3(1) + 18 = 15(1)

-3 + 18 = 15

15 = 15

8 0

2 years ago

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Which set of lengths could not form a triangle? Don´t guess and explain with detailed reasoning.

Ne4ueva [31]

Answer:

8, 12 ,5 I was taking a assignment with that question.

Step-by-step explanation:

7 0

2 years ago

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Brent divided 31/2 by 7 what number did he get

lorasvet [3.4K]

31/2 ÷ 7
= 31/2 ÷ 7/1
= 31/2 × 1/7
= 31/14
= 2/3/14

i am a mathematics teacher. if anything to ask please pm me

3 0

2 years ago

A satellite orbits the Earth with an elliptical orbit modeled by x squared over 43 million eight hundred twenty four thousand fo

morpeh [17]

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is

D= 510 km. Option B. This is further explained below.

<h3>What is Kepler Orbit?</h3>

Generally, In the study of astrodynamics, an ellipse of the satellite is often referred to as a Kepler Orbit

The function of the elliptical orbit is

$\frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1$

compared to

$\frac{(x^2)^2}{47334400}+\frac{(y^2)^2}{43956900}=1$

Hence

a = √(47,334,400 km²)

a= 6,880 km.

In conclusion, The distance of the satellite above the Earth's surface.

D = a - r

D= 6,880 km - 6,370 km

D= 510 km