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Alchen [17]
3 years ago
10

Z=15+2(x+y) solve for x

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0
<span>Z=15+2(x+y) 
Use distributive property
Z= 15 + 2x + 2y
Subtract 2y from both sides
Z - 2y= 15 + 2x
Subtract 15 from both sides
Z - 2y - 15= 2x
Divide 2 on both sides
Final Answer: Z - 2y - 15(All over 2)= x</span>
Rudiy273 years ago
5 0
Z=15+2x+2y
0=15+2x+2y-15
-2x=15+2y-15
x= -\frac{15}{2} - y +  \frac{15}{2}
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A line of roses forms the diagonal of a rectangular flower garden. Th e line of roses is 18.4 m long, and one side of the garden
professor190 [17]
Given that the garden is rectangular and a line of roses form the diagonal 18.4 m long, we required to calculate the length of the perpendicular side.
Here we shall use the Pythagorean theorem.
c²=a²+b²
where c is the hypotenuse, a and b are the legs.
from the information given:
c=18.4 m
a=13 m
plugging this into our expression we get:
18.4²=13²+b²
next we solve for the value of b
b²=18.4²-13²
b²=338.56-169
b²=169.56
b=√169.56
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hence the length to the nearest tenth of a meter will be approximately 13.0 m
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3 years ago
Please solve and explain how. Photo attached
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3 years ago
Which property is illustrated by the following statement 4.8 + k = k + 4.8
Kipish [7]

Step-by-step explanation:

Commutative property

Is illustrated by this statement

8 0
2 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
Which OF THESE IS THE QUADRATIC PARENT FUNCTION!?!
lina2011 [118]

Answer:

D. f(x)=x^2​

Step-by-step explanation:

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