Answer:
The lines are perpendicular, meaning if they were to intersect, they would form four right angles.
By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
Where,
theta: angle in degrees
R: radio
We have then:
(Arc) QPT if <QZT = 120:
theta = 360-120 = 240 degrees
R = 13.5 units
Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
(Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
(Arc) QPT = 56.55 units
Answer:
(Arc) QPT = 56.55 units
Problem 1
Domain = {-1, -3, 2, 1}
Range = {5, 0, 2}
The domain is the set of possible inputs and the range is the set of possible outputs. This is a function because each input goes to exactly one output.
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Problem 2
This is a function as well. We do not have any input going to multiple outputs.
Domain = {-2, -3, 5}
Range = {6, 7, 8}
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Problem 3
This is not a function. The input -4 goes to more than one output (outputs 3 and -1 at the same time)
Domain = {-4, -2, 0}
Range = {3, -1, -2, 4}
It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod <span>9</span><span> are </span><span><span>1</span><span>,4,7</span></span><span> which are came from </span><span><span>1,2,</span><span>4.</span></span><span> </span>Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.
Answer:
Assuming the problem asks to rotate counterclockwise: E' (0,0) F' (0,5) G' (-4,5) H' (-4,0)
If it says rotate clockwise then your points will be: E' (0,0) F' (0,-5) G' (4,-5) H' (4,0)
Step-by-step explanation:
Translate the points first by subtracting 3 from the x-coordinates of each, then subtracting 3 from the y-coordinates of each. Next, to rotate them counterclockwise about the origin 90 degrees, switch the x and y coordinates and the sign of the resulting x-coordinate. To rotate clockwise 90 degrees switch the x and y still but change the sign of the resulting y coordinate.
