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IgorLugansk [536]
3 years ago
9

Josephine noticed that out of 10 e-mails she received, 7 were advertisements. What can she predict about the number of advertise

ments she will receive in the next 100 e-mails?
Mathematics
2 answers:
mojhsa [17]3 years ago
8 0
It would be 70 ads !

andriy [413]3 years ago
4 0
She can expect 70 to be ads since there is 10 times more emails so 7 times 10 is 70 so 70 ads
You might be interested in
Richard can make 8 dough balls in two hours. If the amount of time is directly proportional to the number of dough balls, how ma
Sergio039 [100]

Answer:

4.5 hours

Step-by-step explanation:

8:2h = 18:x

8x = 18×2h

x = 36h/8

x = 4.5

hope this helps :)

8 0
3 years ago
Find the solution of this system of equations. Separate the x- and y-values with a comma. x - 4y = 12 and x - y = 0
Elenna [48]
Use elimination and subtitution method to solve the problem.
First, eliminate x and you'll find the value of y
x - 4y = 12
x -  y  = 0
--------------- - (substract)
     -3y = 12
        y = 12/-3
        y = -4

Second, subtitute -4 as y and you'll find the value of x
x - y = 0
x- (-4) = 0
x + 4 = 0
x = -4

The solution
x,y = -4,-4
6 0
3 years ago
Solve the system of equations displayed in the picture.
bagirrra123 [75]

The answer is D) (-1,-12)

Reason:

1) substitute 2x-10 for y in y=4x-8

2) 2x-10=4x-8

3) -2x-10=-8

4) -2x=2

5) x=-1

6) substitute -1 for x in y=2x-10

7) y=(2)(-1)-10

8) y=-12

Answer

x=-1 and y=-12

7 0
3 years ago
Find the common difference for the arithmetic sequence. 1.7, 2.7, 3.7 4.7.....
Anni [7]

Answer:

Step-by-step explanation:

You do not need to where the formula comes from but, just for fun, here’s a hint

To add up the numbers 1 to 10

Write out the numbers

1 2 3 4 5 6 7 8 9 10

Write them backwards

10 9 8 7 6 5 4 3 2 1

Add up both lists

11  11  11  11  11  11  11  11  11 11

This is 10 × 11 = 110

But this is twice the sum as two lots were added together

So the sum of the numbers 1 to 10 is 110 ÷ 2 = 55

 

ArSeqSum Notes fig4, downloadable IGCSE & GCSE Maths revision notes

5 0
3 years ago
How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy
Ugo [173]

Answer:

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

n \cdot (n+1) < 40000

Now we solve this inequation to the highest value of n that satisfy the inequation:

n^{2}+n < 40000

n^{2}+n -40000

The Quadratic Formula shows that roots are:

n_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (1)\cdot (-40000)}}{2\cdot (1)}

n_{1,2} = -\frac{1}{2}\pm \frac{1}{2} \cdot \sqrt{160001}

n_{1} = -\frac{1}{2}+\frac{1}{2}\cdot \sqrt{160001}

n_{1} \approx 199.501

n_{2} = -\frac{1}{2}-\frac{1}{2}\cdot \sqrt{160001}

n_{2} \approx -200.501

Only the first root is valid source to determine the highest possible value of n, which is n_{max} = 199. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

6 0
3 years ago
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