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3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

mariarad [96]3 years ago

6 0

Answer:

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Step-by-step explanation:

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Line c has an equation of y=-3/4x-3. Line d is parallel to line c and passes through the points (-2, -2). What is the equation o

blagie [28]

Answer:

y = $\frac{3}{4}$ x - $\frac{7}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{3}{4}$ x - 3 ← is in slope- intercept form

with slope m = - $\frac{3}{4}$

Parallel lines have equal slopes , then

y = - $\frac{3}{4}$ x + c ← is the partial equation of line d

to find c substitute (- 2, - 2 ) into the partial equation

- 2 = $\frac{3}{2}$ + c ⇒ c = - 2 - $\frac{3}{2}$ = - $\frac{7}{2}$

y = - $\frac{3}{4}$ x - $\frac{7}{2}$ ← equation of line d

5 0

2 years ago

Volunteers at Sam's school use some of the student council's savings for a special project. They buy 6 backpacks for $4 each and

kaheart [24]

Answer: changed by $48

Step-by-step explanation: 6 times $4 = $24 + $4 times 6 = $24 total= $48

Also $4 times 12 = $48

4 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago

What is $112 in 8 hours

never [62]

Answer:

A unit rate must have a denominator of one:

n/1

So you would get n by dividing 112 by 8: 112 divided by 8 = 14 so n = 14.

14/1 or $14 p/ hr

8 0

3 years ago

What is the measurement 345.067 mg rounded to four significant digits?

Viktor [21]

<span>count four from the first digit to the fourth one. When you see the fourth one, look at the digit after. if it is 5+ then the fourth digit increases by one. if 5- then it stays the same. 6>5 so 0 becomes 1.

Therefore the answer is 345.1mg</span>

4 0

3 years ago

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