X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
Answer:
Speed of wind = 23.63 miles per hour
Plane speed in still air = 260 miles per hour
Step-by-step explanation:
Given:
Time taken with wind = 5 hour
Time taken against wind = 6 hour
Assume;
Speed of wind = s
So,
Speed of Plane with wind = (260 + s) miles per hour
Speed of Plane against wind = (260 - s) miles per hour
Distance = speed x time
So,
(260 + s)5 = (260 - s)6
1,300 + 5s = 1,560 - 6s
11s = 260
s = 23.63 miles per hour
Speed of wind = 23.63 miles per hour
Plane speed in still air = 260 miles per hour
Use point slope form to answer this
Y = x - 10
The user corrected that the scale of a drawing of a park reads: 5 miles to 1 cm , and we know that the park measures 1,600 square meters (user insisted that this measure is given in square meters and not square miles).
So we have to convert the 1600 square meters into miles, knowing that 1 meter is the same as: 0.000621371 miles
then meters square will be equivalents to:
1 m^2 = (0.000621371 mi)^2
then 1600 m^2 = 0.00061776 mi^2
now, since 5 miles are represented by 1 cm, then 25 square miles will be represented by 1 square cm
and therefore 0.00061776 square miles will be the equivalent to:
0.00061776 / 25 cm^2 = 0.000024710 cm^2
So and incredibly small number of square cm.
I still believe that some of the information you gave me are not in meters but in miles. (For example, the park may not be in square meters but in squared miles). The park seems to have the size of a house according to the info.
Answer:A) What are the side lengths of the original triangle, ABC?
B) What are the side lengths of the enlarged, A’B’C?
C) Calculate the area and the perimeter of A’B’C.
