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tresset_1 [31]
3 years ago
11

18. Write an expression to represent the area of the shaded region in simplest form. Please help it's due tomorrow

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

(x^2 + 2x - 21) sq units

Step-by-step explanation:

Area of the shaded region = Area of the larger rectangle - Area of smaller rectangle

Area of the larger region = x(x+2)

Area of the larger region =x^2 + 2x

Area of the smaller rectangle = 3 * 7

Area of the smaller rectangle = 21 sq. units

Area of the shaded region = x^2 + 2x - 21

Hence the required expression is (x^2 + 2x - 21) sq units

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3 years ago
I need help on this please
ziro4ka [17]

Answer:

See answers below

Step-by-step explanation:

From the given functions, the equivalent function for when x = 0 is -(x-1)²

h(x) = -(x-1)²

h(0) = -(0-1)²

h(0)= -(-1)²

h(0) = -1

when x = 2, the equivalent function is -1/2x - 1

h(x) =  -1/2x - 1

h(2) =  -1/2(2) - 1

h(2) = -1-1

h(2) = -2

when x = 5, the equivalent function is -1/2x - 1

h(x) =  -1/2x - 1

h(5) =  -1/2(5) - 1

h(5) = -5/2-1

h(5) = -7/2

3 0
3 years ago
WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the
iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

d=\sqrt{h^2+k^2}

Distance of P from ( -3, 4 ) :

d=\sqrt{(h+3)^2+(k-4)^2}

Now , these distance are equal :

h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2

Solving above equation , we get :

P=(\dfrac{16}{21},\dfrac{23}{7})

Hence , this is the required solution.

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3 years ago
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Alex73 [517]

Answer:

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7 0
3 years ago
Find the value of x.<br> If necessary, you may learn what the markings on a figure indicate.<br> 74°
marissa [1.9K]

Answer:

x = 61

Step-by-step explanation:

Left hand triangle containing 1 angle of 74

Label the other angle opposite the marked side also as 74

Find the third angle. Call it y.

y + 74 + 74 = 180           Combine like terms

y + 148 = 180                 Subtract 148 from both sides.

y = 180 - 148

y = 32

=============

Now work with the triangle on the right.

label the angle making up the right angle = z

32 + z = 90                             These two angles are complementary = 90

32 - 32 + z = 90 - 32              Subtract 32 from both sides

z = 58                                      Use 58 wherever you see z

x + x + z = 180                         Substitute

2x + 58 = 180                          Subtract 58 from both sides

2x = 122                                  Divide by 2

x = 61

5 0
3 years ago
Read 2 more answers
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