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Vaselesa [24]
3 years ago
14

How many kilometers in a marathon​

Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

42.194988

Step-by-step explanation:

There are 42.194988 km in 1 marathon

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There are a total of 225 pupils in Secondary one. If the number of pupils who pay their school fees through GIRO scheme is 14 ti
asambeis [7]
There are several information's already given in the question. Lat us first write them down and then go for solving the problem.

Total number of pupil <span>in Secondary one = 225
Let us assume the number of pupil who do not pay the school fees through GIRO scheme = x
Then
Number </span>of pupil who pay the school fees through GIRO scheme = 14x
So
x + 14x = 225
15x = 225
x = 15
From the above deduction, it can be concluded that 15 pupil did not join the scheme.
8 0
3 years ago
There is a quadrilateral MNPQ in which side MN is congruent to side PQ and side NP is parallel to side MQ. The diagonal MP and t
8_murik_8 [283]

Answer: QN = 12

Step-by-step explanation: This quadrilateral is a paralelogram because its 2 opposite sides (NP and MQ) are parallel and the other 2 (MN and PQ) are congruent.

In paralelogram, diagonals bisect each other, which means QR = RN.

If QR = RN:

QR = 6

Then,

QN = QR + RN

QN = 6 + 6

QN = 12

<u>The diagonal QN of quadrilateral MNPQ is </u><u>QN = 12</u><u>.</u>

5 0
3 years ago
Fred and Ben each ran laps around the track. Fred completed his run in 16 minutes. Ben completed his run in 3/4 of the amount of
m_a_m_a [10]

Answer:

Time required by Ben was 12 minutes.

Step-by-step explanation:

Given:

Time Required for Fred = 16 mins

Ben completed his run in 3/4 of the amount of time of Freds run.

We need to find the time required by Ben.

Now Given that;

Ben completed his run in 3/4 of the amount of time of Freds run.

It means that time required by Ben is equal to 3/4  times time required by Fred.

Time required by Ben = \frac{3}{4}\times  Freds \ run

Time required by Ben = \frac{3}{4}\times 16 = 12\ mins

Hence Time required by Ben was 12 minutes.

7 0
3 years ago
adam prepares a meal of shrimp and brown rice. it must contain exactly 6 g of fat and 10 mg of iron. each 5oz serving of shrimp
jasenka [17]

Answer:

Adam needs 9/8 of a 5oz serving of shrimps (which equals to 5.625 oz) and 5/8 of a cup of brown rice (which is around 10 tablespoons).


Explanation:

You are given:

every serving of shrimp contains 2g of fat and 5mg of iron;

every serving of rice contains 6g of fat and 7mg of iron;

each meal should have 6g of total fat and 10mg of total iron.


You need to set a system of equation: let's call

s = quantity of shrimps

r = quantity of rice

The equation for the total fat will be: the quantity of fat in the serving of shrimps plus the quantity of fat in the serving of rice must be equal to 6g

2s + 6r = 6    (1)

Similarily:

the quantity of iron in the serving of shrimps plus the quantity of iron in the serving of rice must be equal to 10g

5s + 7r = 10     (2)


In order to solve the system, solve for s in equation (1):

s = (6-6r)/2 = 3 - 3r        (3)

Substitute in equation (2):

5(3 - 3r) + 7r = 10

and solve for r:

15 - 15r + 7r = 10

8r = 5

r = 5/8

Substitute the value of r in equation (3):

s = 3 - 3×5/8 = 9/8


Therefore Adam would need 9/8 of a 5oz serving of shrimps and 5/8 of a 1 cup of brown rice for each meal.

6 0
3 years ago
True or False: In order to solve an equation, we must isolate the variable.
vaieri [72.5K]

Answer:

It is False

But it's not true

3 0
2 years ago
Read 2 more answers
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