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ipn [44]
3 years ago
15

What is the function for a table with a domain of 5, 10, 15, 20 and a range of 40, 80, 120, and 160

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
To find the range we need to find the vertex of the parabola which is at (-b/2a , y)

-b/2a would be 2/2 = 1 ... so find the y value at x = 1

12 - 2(1) - 15 = 1-17 = -16

So the vertex is at (1,-16)

Since the parabola opens upward from that point the minimum value of the range is y = -16

The range would include the point -16 so it is actually

R = [-16,infinity)

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A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
saul85 [17]

Answer:

The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

He takes a simple random sample of 122 people living in Gastown and finds that 25 have an annual income that is below the poverty line. This means that n = 122 and \pi = \frac{25}{122} = 0.205

We have \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.205 - 1.96\sqrt{\frac{0.205*0.795}{122}} = 0.133

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.205 + 1.96\sqrt{\frac{0.205*0.795}{122}} = 0.133 = 0.2766

The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).

7 0
3 years ago
Three friends are sharing $76. They keep a record of what they do. First they split up the $10 bills.
Basile [38]

Answer:

2 in bottom box and 1 in top box

5 0
3 years ago
Read 2 more answers
Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet d
kari74 [83]
After first week pond will be:
10 + 10* 0.03 = 10*(1.03) feet deep
after second week it will be:

10*(1.03) + 10*(1.03)*0.03 = 10*(1.03)^2

from this we can conclude that after x week its will be:
10*(1.03)^x

Note that when second week starts our starting pond is already greater by 3%. every week we add 3% of prevous weeks size of pond

for x = 8 we get
f(x) = 10*(1.03)^8 = 12.66 or rounded 13 feet

Answer is D.

5 0
4 years ago
Can someone help asap
Komok [63]

Part A:

Expression: 21 = 8h + 179

Part B:

21 = 8h + 179

h = - 19

Move 179 to the other side by subtracting 179 from both sides.

21 - 179 = -158

-158 = 8h

Then, divide both sides by 8 to get the feet descended per hour.

-158/8 = -19

h = -19

Therefore, Luther and Nicole descend approximately 19 feet per hour.

4 0
3 years ago
Which inequality best represents the domain of the part shown<br>​
Alchen [17]

Answer:

there is no question upload it

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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