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ipn [44]
3 years ago
15

What is the function for a table with a domain of 5, 10, 15, 20 and a range of 40, 80, 120, and 160

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
To find the range we need to find the vertex of the parabola which is at (-b/2a , y)

-b/2a would be 2/2 = 1 ... so find the y value at x = 1

12 - 2(1) - 15 = 1-17 = -16

So the vertex is at (1,-16)

Since the parabola opens upward from that point the minimum value of the range is y = -16

The range would include the point -16 so it is actually

R = [-16,infinity)

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Answer:

f en el chat box

Step-by-step explanation:

5 0
3 years ago
A small company that manufactures snowboards uses the relation below to model its profit. In the model,
amm1812

Answer:

a)   x₁ = 14

     x₂ = - 6

b) x = 4

c) P(max ) = 4000000 $

Step-by-step explanation:

To find the axis of symmetry we solve the equation

a) -4x² + 32x + 336 = 0

4x²  - 32x  - 336  = 0       or    x² - 8x - 84 = 0

x₁,₂ = [ -b ± √b² -4ac ]/2a

x₁,₂ = [ 8  ±√(64) + 336 ]/2

x₁,₂ = [ 8  ± √400 ]/2

x₁,₂ =( 8 ± 20 )/2

x₁  = 14

x₂ = -6

a) Axis of symmetry must go through the middle point between the roots

x = 4 is the axis of symmetry

c) P = -4x² + 32x + 336

Taking derivatives on both sides of the equation we get

P´(x) = - 8x + 32  ⇒  P´(x) = 0     - 8x + 32

x = 32/8

x = 4    Company has to sell  4 ( 4000 snowboard)

to get  a profit :

P = - 4*(4)² + 32*(4) + 336

P(max) = -64  + 128 + 336

P(max) = 400           or  400* 10000 =  4000000

     

8 0
3 years ago
What do the solutions of a quadratic equation represent graphically? What is the maximum number of solution(s) given by solving
astra-53 [7]

Answer:

The solutions of a quadratic equation on a graph is the point where the graph cuts across the x and y axes. The maximum number of solutions given by solving a quadratic equation is 2 solutions because the maximum power in a quadratic equation is power 2

8 0
3 years ago
The Regency Hotel has enough space at its entrance for six taxicabs to line up, wait for guests, and then load passengers. Cabs
maksim [4K]

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Step-by-step explanation:

According to the question, the values will be:

The service rate of guess will be:

= 5+3.5

= 8.5 \ minutes

The mean arrival rate will be:

\lambda =\frac{60}{5}

  =7.5 \ cabs/hr

The mean service rate will be:

\mu= 7.05 \ cabs/hr

(1)

The average time a cab must wait will be:

⇒ W_q=22.95-\frac{1}{7.05}

⇒       =\frac{161.798-1}{7.05}

⇒       =\frac{160.798}{7.05}

⇒       =22.81 \ minutes

(2)

The required probability will be:

⇒ P(X\geq 6)=\frac{1-2.115}{1-7.5}

⇒                  =\frac{-1.1115}{-6.5}

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6 0
3 years ago
What table could represent a linear function??? plz help
Strike441 [17]

Answer:

2

Step-by-step explanation:

the column (x) the numbers go up by 4 every time and the (y) column goes up  by 7 every time

6 0
3 years ago
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