The power of 10 is -5
Move the decimal point to the right until the first significant number and in this problem it is 2. It took 5 places to the right until going past the 2 and the number would be negative because going right past the decimal point will make any power negative.
Answer:
x^3-10x^2+x+120
Step-by-step explanation:
Assuming you mean roots -3, 5, 8
These happen when we have (x+3)(x-5)(x-8)=0
Expand this
(x^2-2x-15)(x-8)=0
=x^3-2x^2-15x-8x^2+16x+120
=x^3-10x^2+x+120
Answer:
-5/3
Step-by-step explanation:
Do PEMDAS
8 - 11 = -3
-3 ^ 3 = -27
-(-27) = 27
I-14I = 14
3 x 14 = 42
27 - 42 = -15
2^4 = 16
16 - 7 = 9
-15/9 = -5/3
Answer:
solution set is (x,y) = (7,6)
Step-by-step explanation:
solving by substitution method
2x +y=20--------------1
6x-5y=12---------------2
from equation 1, solve for y
2x+y=20
y= 20-2x------equation 3
adding value of y in equation 2
6x-5y=12
6x-5(20-2x)=12
6x-100+10x=12
16x= 12+100
16x= 112
x= 112/16
x=7
adding value of x in equation 3
y= 20-2x
y= 20- 2(7)
y=20-14
y=6
so solution set (x,y) = (7,6)
