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2 years ago

A group of 493 people is going on a boat tour. If each boat holds 7 people, how many people will be on the last boat?

Mathematics

1 answer:

Rudik [331]2 years ago

8 0

Answer:

3 people.

Step-by-step explanation:

493÷7=70 with 3 remaining.

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Use the following equation to answer the questions below:

Lina20 [59]

Answer:

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3 years ago

85 on a 7-hour clock

mihalych1998 [28]

Answer.

Step-by-step explanation:

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3 years ago

I will give u 100 points and mark you as brainiest if you can answer this for me pls I need it I am in a quiz Order –17, –14, an

Dafna1 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

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2 years ago

Can you guys help me out.

mrs_skeptik [129]

Answer:

y = -21

Step-by-step explanation:

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3 years ago