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LuckyWell [14K]
3 years ago
6

You are preparing small and large cupcakes for the school bake sale. If you will need 1 3 a spoon of sugar for each small cupcak

e, and 1 2 a spoon of sugar for the large cupcake. If you need to make 30 small cupcakes and 20 large cupcakes, and you have a total of 21 spoons of sugar. Is this enough to make your cupcakes?
Mathematics
1 answer:
vekshin13 years ago
4 0

the answer is possibly I don’t know

Step-by-step explanation:

You might be interested in
If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

3 0
3 years ago
Solve the equation for all values of x in simplest form:<br> (x - 2)2 = 49
marin [14]
2x-4=49
2x=54
x is equal to 27
3 0
3 years ago
Solve using elimination.<br> 8x – 6y = -6<br> 2x – 4y = -14
vovangra [49]
I’m not sure if you want the answer or how to do i’ll just give you both.
multiply the bottom by -4. then it should look like:
8x-6y=-6
-8x+16y=56
then cancel out the x’s and add/subtract the others, giving you: -2y=50. then divide 50 by -2 giving you: y=-25. then find x. plug in y to one of the equations. i usually do the one that hasn’t been messed with. 8x-6(25)=-6. then solve it like a normal two-step equation.
so the answer is: (18,-25)
7 0
3 years ago
Solve -mk - 90&gt; 85 solve for m
Vikentia [17]
Let's solve for k. (-m)(k) - 90>85

step 1: add 90 to both sides.
-km -90+90> 85+90
- km > 175

step 2: divide both sides by -m
-km >175
-m -m

K< -175
m
7 0
3 years ago
Please answer this correctly without making mistakes
kolbaska11 [484]

Answer:

1,377/2 and 688 1/17

Step-by-step explanation:

4 0
2 years ago
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