Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Answer:
kjhgikoljuuihg
Step-by-step explanation:
bgkjm
13t-13t=0
so your left with
6=12
which is a false statement which makes this equation have no solutions
Answer:
b
Step-by-step explanation:
because it is -2 four times and if you do -2 ×4 you get -8. hope thid helped
Answer:
3,000 people
Step-by-step explanation:
Total number of people larger stadium can hold equals 4.5 times 
people,
which equals 45,000 people.
Now,
it is given that larger stadium can hold 15 times more people than small stadium .
So, smaller stadium will hold 15 times less people than the larger stadium ,
Which equals , 
= 3,000 people.
Thus ,
Smaller stadium can hold a total of 3,000 people.
