The size of each interior angle of a regular polygon is 8 times the sizes of each exterior angle.
2 answers:
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The answer is a = 3/4 = 0.75
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
![\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%20%7Ba%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B81%7D%20%20%20%5C%5C%20%204a%20%3D%203)
Divide both sides by 4:
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
Divide both sides by 4:
Rational expressions are those that have fractional terms. We state restrictions because it may cause the equation to be undefined in some values of x. The most common restriction for rational expressions is N/0. This means any number divided by zero is undefined.
<h3>What is rational expressions and examples?</h3>A rational expression is nothing more than a fraction in which the numerator and/or the denominator are polynomials. Here are some examples of rational expressions.
To find the restrictions on a rational function, find the values of the variable that make the denominator equal 0.
Learn more about rational expressions here:
y = slope (x) + y - intercept
To find the slope we need to find out how much the x's and y's increase or decrease...
To find the y - intercept if any, simply look for coordinates ( 0 , y ) or 0 and a #.
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In this case, as time passes, the water level decreases therefore we have a negative slope.
Time is our x and amount (ft) is our y.
On the x side it increases by 2
On the y side it decreases by 10
Now do y over x ==> 10 over 2 and get 5 ==> m
-5 is our slope and 50 is our y - intercept
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The "rate of change" is another word for slope.
Well, slope is - 5ft is our slope.
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I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey