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3 years ago

The size of each interior angle of a regular polygon is 8 times the sizes of each exterior angle.

Mathematics

2 answers:

GuDViN [60]3 years ago

6 0

Answer:

18 sides

Step-by-step explanation:

Exterior angle: x = 360/n

Interior angle: 8x = (n-2)×180/n

(n-2)×180/n = 8 × 360/n

n - 2 = 16

n = 18

olga55 [171]3 years ago

5 0

Answer:

Step-by-step explanation:

To find the value of a given exterior angle of a regular polygon, simply divide 360 by the number of sides or angles that the polygon has. For example, an eight-sided regular polygon, an octagon, has exterior angles that are 45 degrees each, because 360/8 = 45.

If each interior angle is 8 times the degree measure of each exterior angle how many sides does the polygon have. Now 8+1 = 9. Divide 180 by 9 to get 20.

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If Travis tries to drink 3 quarts of water each day how many cups of water does he drink each day

olchik [2.2K]

He would drink 12 cups of water a day. There are 4 cups in a quart so 4 times 3 is 12.

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3 years ago

3. A sign company is building a sign with the dimensions shown. What is the area, in square feet, of the sign? Round to the near

Aleks04 [339]

Answer:

84.87sq ft

Step-by-step explanation:

Let ABC be the triangle and AD be the perpendicular on BC such that BD=DC=7ft.

Now, it is known that $\frac{DC}{AC}=cos60^{0}$

$AC=\frac{7}{\frac{1}{2}}$

$AC=7ft$

Now, in triangle ADC, we have

$(AC)^{2}=(AD)^{2}+(DC)^{2}$

$(14)^{2}=(AD)^{2}+(7)^{2}$

$196-49=(AD)^{2}$

$AD=12.12ft$

Now, area of the triangle= $\frac{1}{2}{\times}b{\times}h$

= $\frac{1}{2}{\times}14{\times}12.12$

= $84.87sq ft$

Thus, area of the building is 84.87sq ft.

8 0

3 years ago

PLSS help me with this and show your work

hodyreva [135]

hii

3x-1/5=x+1/3

3[3x-1]=5[x+1]

9x-3=5x+5

9x-5x=5-3

4x=2

x=2/4

x=1/2

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

6 0

3 years ago

Read 2 more answers

Can someone give me the answers and step by step instructions please??

professor190 [17]

Answer:

$-1,4,-7,10,...$ neither

$192,24,3,\frac{3}{8},...$ geometric progression

$-25,-18,-11,-4,...$ arithmetic progression

Step-by-step explanation:

Given:

sequences: $-1,4,-7,10,...$

$192,24,3,\frac{3}{8},...$

$-25,-18,-11,-4,...$

To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them

Solution:

A sequence forms an arithmetic progression if difference between terms remain same.

A sequence forms a geometric progression if ratio of the consecutive terms is same.

For $-1,4,-7,10,...$ :

$4-(-1)=5\\-7-4=-11\\10-(-7)=17\\So,\,\,4-(-1)\neq -7-4\neq 10-(-7)$

Hence,the given sequence does not form an arithmetic progression.

$\frac{4}{-1}=-4\\\frac{-7}{4}=\frac{-7}{4}\\\frac{10}{-7}=\frac{-10}{7}\\So,\,\,\frac{4}{-1}\neq \frac{-7}{4}\neq \frac{10}{-7}$

Hence,the given sequence does not form a geometric progression.

So, $-1,4,-7,10,...$ is neither an arithmetic progression nor a geometric progression.

For $192,24,3,\frac{3}{8},...$ :

$\frac{24}{192}=\frac{1}{8}\\\frac{3}{24}=\frac{1}{8}\\\frac{\frac{3}{8}}{3}=\frac{1}{8}\\So,\,\,\frac{24}{192}=\frac{3}{24}=\frac{\frac{3}{8}}{3}$

As ratio of the consecutive terms is same, the sequence forms a geometric progression.

For $-25,-18,-11,-4,...$ :

$-18-(-25)=-18+25=7\\-11-(-18)=-11+18=7\\-4-(-11)=-4+11=7\\So,\,\,-18-(-25)=-11-(-18)=-4-(-11)$

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.

3 0

3 years ago

What happens to the particles in iodine when you increase

Tju [1.3M]

Answer:

When you have iodine gas at 200 degrees, the temperature and thus pressure as so high, that when cooling down you enter the liquid phase. And when some of this gas then condenses, the pressure drops. So the remaining part of the gas can sublime.

Step-by-step explanation:

5 0

3 years ago