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2 years ago

I need help pls! i’m kinda s t u p i d! lol

Mathematics

1 answer:

LiRa [457]2 years ago

3 0

The answer is b or no
i hope this helped

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20 POINTS AND BRAINLIEST Ed has 93 marbles. In which sequence can he arrange them in to use all the marbles?

horsena [70]

Answer:

D. A sequence with 5 terms that starts with 3 and has a common ratio of 2

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3 years ago

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2/3 is less than 4/5 true or false

mojhsa [17]

Answer: False

Step-by-step explanation:

When comparing fractions such as 2/3 and 4/5, you could also convert the fractions (if necessary) so they have the same denominator and then compare which numerator is larger.

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3 years ago

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Find the area between the graph of the function and the x-axis over the given interval, if possible.

vodomira [7]

Answer:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

$A = \int_{-\infty}^1 \frac{5}{(x-2)^2}$

For this case we can use the following substitution $u = x-2$ and we have $dx = du$

$A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du$

And if we solve the integral we got:

$A= -\frac{5}{u} \Big|_a^b$

And we can rewrite the expression again in terms of x and we got:

$A = -\frac{5}{x-2} \Big|_{-\infty}^1$

And we can solve this using the fundamental theorem of calculus like this:

$A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5$

So then the integral converges and the area below the curve and the x axis would be 5.

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3 years ago

Find the gcf of 200 and 72

Aleks04 [339]

To get the Greates Common Factor (GCF) of 72 and 200 we need to factor each value first and then we choose all the copies of factors and multiply them:

72: 22233 200: 222 55GCF: 222

The Greatest Common Factor (GCF) is: 2 x 2 x 2 = 8

Answer: 8

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3 years ago

Look at this expression.

Soloha48 [4]

Answer:

c 18

Step-by-step explanation:

Idid thsi in Kahn academy and got it correctly

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2 years ago