Answer:
1
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
2
+
5
−
2
=
0
x^{2}+5x-2=0
x2+5x−2=0
=
1
a={\color{#c92786}{1}}
a=1
=
5
b={\color{#e8710a}{5}}
b=5
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
5
±
5
2
−
4
⋅
1
(
−
2
)
√
2
⋅
1
Step-by-step explanation:
this should help
Answer:

Step-by-step explanation:
<u>Step 1: Pull a 7 from the top</u>
<u />

<u>Step 2: Factor the bottom</u>
<u />
<u>Step 3: Cancel the top (x+6) and the bottom (x+6)</u>
<u />
Answer: 
It would be
3.5 × 10⁻³ kg.
The decimal point must be moved 3 places to the right in order to have it behind the first non-zero digit; this gives us the exponent of 3, and since we are moving the decimal to the right, it is a negative exponent.
Answer:
(1 L = 33.8 oz)
Step-by-step explanation:
Answer and Step-by-step explanation:
To simplify, distribute the negative number.
-(11 + 2b)
<u>-11 - 2b is the answer.</u>
<u></u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
<em><u></u></em>
<em><u>I hope this helps!</u></em>