3 years ago

Find the area of these Trapezoid

Mathematics

1 answer:

nlexa [21]3 years ago

7 0

Answer:

you can find it by 1/2a+bxh

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Someone can help??

oee [108]

Answer:

Step-by-step explanation:

let cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

$\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}} \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}$

4 0

4 years ago

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x2 + 9x?

inn [45]

Hello :
y = 3x²+9x
= 3(x² + 3x )
= 3 ( x² +2(3/2)x +(3/2)²) -(3/2)²)
= 3((x+3/2)² -9/4)
y = 3 (x+3/2)² -27/4
<span>the x-coordinate of the vertex is : - 3/2</span>

8 0

3 years ago

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Consider the arithmetic sequence 13, 16, 19, 22, 25, ...<br> What is the 60th term in the sequence?

Pavel [41]

Answer:

180

Step-by-step explanation:

6 0

3 years ago

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PLEASE HELP, I'LL MARK BRAINLY (EASY)!