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son4ous [18]
3 years ago
6

Ftgtggggygggggggghhhhhhggghggggggggfffffff

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0

c.
greater than and less than signs have dotted lines.
greater than or equal to and less than or equal to have solid lines.
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H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?
lara31 [8.8K]

Answer:

(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}

Step-by-step explanation:

h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \  respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x

For positive rate of change h'(x)>0

\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\

6 0
3 years ago
What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375
Anna [14]
C. 427

The median is the middle number of all the data

Since there is an even number of data points the median is in between the middle two data points (434 and 420)

To find this: 434-420=14
14/2=7
434-7=427
420+7=427
8 0
3 years ago
Place is highest to lowest 3/4 84% 1/3 0.82
sesenic [268]

ANSWER

84%,0.82,¾,⅓

EXPLANATION

Convert everything to decimals.

\frac{3}{4}  = 0.75

84\% = 0.84

\frac{1}{3}  = 0.333....

The last one is already in decimals.

0.82

We can now see clearly, that

0.84  \: > \:  0.82 \:  >  \: 0.75  \: >  \: 0.3333...

This implies that,

84\% \: > \:  0.82 \:  >  \:  \frac{3}{4}   \: >  \:  \frac{1}{3}

Hence from highest to least, we have

84%,0.82,¾,⅓

4 0
4 years ago
Julies buys 8.2 pounds of pears for $16<br><br> ABOUT how much do they cost per pound?
RoseWind [281]

Answer:

$1.95 or 2. According to your refrences.

Step-by-step explanation:


4 0
3 years ago
A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​
allsm [11]
  • Initial velocity=u=0m/s
  • Distance=s=150m
  • Time=t=10s
  • Acceleration=a

Using second equation of kinematics

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2

\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a

\\ \sf\longmapsto 50a=150

\\ \sf\longmapsto a=\dfrac{150}{50}

\\ \sf\longmapsto a=3m/s^2

  • Mass=m=1000kg
  • Force=F

Using newtons second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto F=1000(3)

\\ \sf\longmapsto F=3000N

3 0
3 years ago
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