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rodikova [14]
3 years ago
7

I need help on these questions

Mathematics
1 answer:
Advocard [28]3 years ago
4 0
For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.

for # 3:
we know A = pi r^2
We have 
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04

for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92

for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582
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Gina has a jar of marbles that contains 7 blue marbles, 5 red marbles, and 8 green marbles. She randomly selects a marble, recor
BigorU [14]

The probability that Gina randomly selected two red marbles is 1/19

<u>Explanation:</u>

Total number of marbles = 7 + 5 + 8

                                          = 20

The probability of getting two red marbles in the fraction form is given as:

P(first red marble) = number of red marbles / total number of marbles

P(first red marble) = \frac{5}{20} = \frac{1}{4}

P(second red marble) = number of red marbles after 1 white marble is removed / total number of marbles after 1 red marble is removed.

P(first red marble) = \frac{4}{19}

P(two red marbles) = P(first) X P(second)

                              = \frac{1}{4} X \frac{4}{19}

                              = \frac{1}{19}

Therefore, the probability that Gina randomly selected two red marbles is 1/19

6 0
3 years ago
Please Please Please help with this math problem
katovenus [111]
  1. The revenue as a function of x is equal to -x²/20 + 920x.
  2. The profit as a function of x is equal to -x²/20 + 840x - 6000.
  3. The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
  4. The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

3 0
2 years ago
I need help in math :(
IgorLugansk [536]
B. 8 1/5 is the answer
7 0
3 years ago
Read 2 more answers
Ann had 45 fliers to post around town. Last week, she posted 2/3 of them. She posted 1/3 of the remaining fliers. How many flier
Bess [88]

Answer:

48

Step-by-step explanation:

(1/4)16 = 4

48-32-4 = 12 still not posted

checking

32 + 4 + 12 = 48 CHECKS!

7 0
3 years ago
Read 2 more answers
How do you answer number 5
riadik2000 [5.3K]

x² - x - 6  = (x +3)(x - 2)

x² - 5x + 6 = (x - 2)(x - 3)

What is their common factor?

Answer: B. x - 2

5 0
3 years ago
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