Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer:
-22 + (-16)= -38
Step-by-step explanation:
Answer:
y = 9.8x + 6.7
y = 6.7x + 9.8
y = 7.5x + 3.8
y = 3.8x + 7.5
Step-by-step explanation:
I made 2represent x.
y= 9.8(2) + 6.7
y = 26.3
y=6.7(2) + 9.8
y= 23.2
y= 7.5(2) + 3.8
y= 18.8
y= 3.8(2) + 7.5
y= 15.1
M = (22 - 7)/(8 - 5) = 15/3 = 5
<span>using point (5, 7) </span>
<span>y - 7 = 5(x - 5) in point-slope form </span>
<span>y - 7 = 5x - 25 </span>
<span>y = 5x - 18 in slope-intercept form.</span>
