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3 years ago

Can someone help me with this question please

Mathematics

2 answers:

DaniilM [7]3 years ago

6 0

Answer:

Step-by-step explanation:

1,2,5 have the same ratio as 4,8,20 and add up to 32

Inessa05 [86]3 years ago

6 0

Answer:

First problem: 2sqrt(5)

Second problem: 20 ft

Step-by-step explanation:

First problem:

The geometric mean, x, of a and b is

a/x = x/b

Here you have 4 and 5, so the geometric mean, x, of 4 and 5 is

4/x = x/5

Cross multiply.

x^2 = 4 * 5

x = sqrt(4 * 5)

x = 2sqrt(5)

Second problem:

Ratio of lengths of sides is

1 : 2 : 5

Add all numbers, 1 + 2 + 5 = 8

The ratio of the longest side to the perimeter is

5 : 8

Let the longest side have length x.

5/8 = x/32

8x = 5 * 32

8x = 160

x = 20

Answer: 20 ft

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3 years ago

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3 years ago

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

stiks02 [169]

Answer:

$0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026$

$0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073$

The 90% confidence interval would be given by (0.026;0.073)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated proportion for this case is:

$\hat p =\frac{322-306}{322}= 0.0497$

Represent the proportion of defectives for this case

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: