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Nataliya [291]
3 years ago
6

Find B if a= 8M, B=69°, and C=48°​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

Step-by-step explanation:

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Find x <br> Plz help me !!!
mel-nik [20]

Answer:

\Huge\boxed{x=33.2}

Step-by-step explanation:

Hello there!

We can solve for x using law of sines

As we can see in the image a side length divided by sin ( its opposite angle) = a different side length divided by sin ( its opposite angle)

So we can use this equation to solve for x

\frac{21}{sin(35)} =\frac{x}{sin(65)}

Our objective is to isolate the variable using inverse operations so to get rid of sin (65) we multiply each side by sin (65)

\frac{x}{sin(65)} sin(65)=x\\\\\frac{21}{sin(35)} sin(65)=\frac{21sin(65)}{sin(35)}

we're left with

x=\frac{21sin(65)}{sin(35)}\\x=33.18208755

assuming we have to round the answer would be 33.18 or 33.2

7 0
3 years ago
I have no clue what to do please help
poizon [28]
With the whole question ???
8 0
3 years ago
Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

8 0
3 years ago
Find the circumference and area of the circle having a given diameter of d = 13 cm
expeople1 [14]
Circumference of circle = pi*diameter = 13pi cm

Area is pi*d^2/4 = pi*13^2/4 = 42.25pi cm^2.
5 0
3 years ago
Ann believes that y= 3x (x -7) is a quadratic function. Jordan says that she is wrong because the degree (highest exponent) is n
ad-work [718]

Answer:

Ann us correct. It's a quadratic function.

Step-by-step explanation:

Given equation is,

y = 3x(x - 7)

By converting this equation into the standard quadratic equation,

y = 3x² - 21x

Highest exponent of the polynomial equation is 2 (Exponent of highest degree variable x²). This decides that the given function is a quadratic function.

Therefore, Ann is correct. It's a quadratic function.

5 0
3 years ago
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