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Schach [20]
3 years ago
7

Can anybody help me with this please I’ll mark you as a brainliest.

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Answer:

its 3.

Step-by-step explanation:

plz mark brainliest :) :))))))))))))

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a line with the slope of -5 passes through the points (-3, -5) and (-4, teat parentheses. What is the value of t​
Setler79 [48]

Step-by-step explanation:

First, find the slope using the slope formula

m = (Y2 - Y1)/(X2 - X1).

Then use the point slope formula,

Y - Y1 = m(X - X1), with one of the given

points and the slope. Also, solve for y.

Use Y - Y1 = m(X - X1)

Also, solve for y.

Find the slope of the given line, m, by rewriting the given equation in y = mx + b. Flip and change the sign on the given slope to find the new slope.

Use Y - Y1 = m(X - X1)

Plug in the given point and new slope

and solve for y.

Plot points or graph line. Move a vertical line across the graph. If the line touches more than once then it is not a function.

Domain = { x-values, ... }

Range = { y-values, ... }

List the elements in increasing order and don't repeat.

For this class, the domain is all real numbers unless you have an x in the denominator of a fraction.

When x is in the denominator, set the denominator equal to zero and solve. Everything on a number line works except the value(s) you got when solving.

Answer: (- infinity, #) u (#, infinity)

Parentheses everywhere b/c the number # does not work in the equation.

Domain: Squish the graph to the x-axis. Write shaded part in interval notation (left, right)

Range: Squish the graph to the y-axis. Write shaded part in interval notation (down, up)

Brackets include points, parentheses don't. Infinities always get parentheses.

Write both equations in the style y = mx + b.

Look at the slopes, m, to answer the question.

If the slopes are the same, then they are parallel.

If the slopes are negative reciprocals, then they are perpendicular. Otherwise, neither.

If you have an equal to under the inequality, then you have a solid boundary line. If you don't have an equal to under the inequality, then you have a dotted boundary line.

After you have graphed the boundary line and determined if it is solid or dotted, find a test point on either side of the boundary line. Substitute the ordered pair into the original inequality. If it simplifies down to a true statement, shade the region where that point is. If it is false, shade the region that does not contain that point.

7 0
2 years ago
A system of linear inequalities is shown below.
Helga [31]
A) Isolate y in both inequalities

1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3

B) Draw the lines for the following equalities:

1) y = 4 - x
2) y = 2x - 3

C) Shade the regions of solutions

1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3

The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3


5 0
3 years ago
Sally's summer punch recipie is a combo of lemonade and fruit punch.
creativ13 [48]

Answer:

anything else?

6 0
3 years ago
Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place.
Mila [183]

Step-by-step explanation:

the total area = the area of full circle + the area of parallelogram = (π ×(8/2)²) + (28×7)

= (3,14 ×16)+(196)

= 50,24 +196

= 246,24

= 246,2

7 0
3 years ago
What is the product?
Leya [2.2K]

Answer:

5/4k^2

Step-by-step explanation:

P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.

We will be using the following property of exponents:

\dfrac{a^x}{a^y}=a^{x-y}.

We have

P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.

Thus, the required product is \dfrac{5}{4k^2}.

Read more on Brainly.com - brainly.com/question/8858421#readmore

8 0
3 years ago
Read 2 more answers
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