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lara31 [8.8K]
1 year ago
9

What will the coordinates of Triangle RST be after it is translated 4units down and 3 units left

Mathematics
1 answer:
mote1985 [20]1 year ago
8 0

Triangle RST has vertices:

R(-4,2)

S(3,5)

T(-4,-4)

Then, the triangle is moving to the left you subtract the number of units from the x coordinates of each vertex of the triangle.

And the triangle is moving down, you subtract the number of units moved down from the y coordinates of each vertex. So:

For R'

(-4-3,2-4)=(-7,-2)

For S'

(3-3,5-4)=(0,1)

For T'

(-4-3,-4-4)=(-7,-8)

Answer:

\begin{gathered} R^{\prime}(-7,-2) \\ S^{\prime}(0,1) \\ T^{\prime}(-7,-8) \end{gathered}

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What is the value of x?
Alex_Xolod [135]

Answer:

x=4

Step-by-step explanation:

ABCD is a rectangle, so AD and BC are parallel. Thus, The angle complementary to 6x+19 is 47.

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WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0
4 years ago
Let P (x, y) be the statement "Student x has taken class y," where the domain for x consists of all students in your class and f
Rufina [12.5K]

Answer: Hello mate!

we know that p(x,y) means "Student x has taken class y"

and the used symbols are:  

∃: this means "existence", you use this symbol to say that there exists at least one object that makes true the sentence.

∀: this means "for all", you use this symbol to say that the sentence is true for all the elements, then:

a) ∃x∃yP (x, y)

"exist at least one student x, that took at least one class y"

b) ∃x∀yP (x, y)

"exist at least one student x, that took all the classes y"

c) ∀x∃yP (x, y)

"every student x, took at least one class y"

d) ∃y∀xP (x, y)

"exist at least one class y, that has been taken by all the students x"

e) ∀y∃xP (x, y)

"for every class y, there is at least one student x that took the class"

f) ∀x∀yP (x, y)

"all the students x took all the classes y"

4 0
3 years ago
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