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Finger [1]
2 years ago
10

A) Each exterior angle in a regular n-gon measures 40˚. How many sides does this n-gon have?

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
6 0

Answer:

Because it is a regular polygon, the sum of all exterior angles is equal to 360 degrees (one revolution). If each side has an exterior angle of 40 degrees, we simply divide 360 by 40 to get 9.

Step-by-step explanation:

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Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

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3 years ago
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Mazyrski [523]

Answer:

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We are given that a coin is toseed with two possible outcomes (head or tails) and a ball from a ball with balls of three different colors is picked.

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