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notsponge [240]
3 years ago
9

Determine if the statement is always, sometimes or never true. Equilateral triangles are isosceles triangles.

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0
Never .. isoscels is unequal. I'm pretty sure
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The selling price of a dining table is $250.00, the markup is 40%. What is the cost of the table?
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Answer to this question
777dan777 [17]

Answer:

3/2

Step-by-step explanation:

Rewrite the equation by swapping x by y.

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The polynomial 6x2 x − 15 has a factor of 2x − 3. what is the other factor? 3x − 5 3x 5 4x − 5 4x 5
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6x^2 + x - 15 = 6x^2 - 9x + 10x - 15 = 3x(2x - 3) + 5(2x - 3) = (3x + 5)(2x - 3)
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Read 2 more answers
2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you
ANEK [815]

Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

7 0
3 years ago
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