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malfutka [58]
3 years ago
13

Please help !

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0

Answer:

New line =3*ZX

Step-by-step explanation:

It is given that the isosceles trapezoid is dilated using a scale factor of 1/3

and a line is drawn through the center of the new dilated figure, so

let us suppose that line is EF which is drawn and it will also pass through

the center in similar way the line ZX passes through so after considering this situation, we can come to this point

\text{new Line EF}=\frac{ZX}{1/3} \\EF=3*ZX

so new line will be 3 times longer than ZX.

You might be interested in
Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r
Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

(x',y')=(-x, y), \forall\, x, y\in \mathbb{R} (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

(x',y') =(x-3,y+2), \forall \,x,y\in \mathbb{R} (Eq. 2)

Where:

(x, y) - Original point, dimensionless.

(x', y') - Transformed point, dimensionless.

If we know that F(x,y) = (-2, 4) and G(x,y) = (-2,-3), then we proceed to make all needed operations:

Translation

F''(x,y) = (-2-3,4+2)

F''(x,y) = (-5,6)

G''(x,y) = (-2-3,-3+2)

G''(x,y) = (-5,-1)

Reflection

F'(x,y) = (5, 6)

G'(x,y) = (5,-1)

Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:

F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}

F'G' = 7

The length of the segment F'G' is 7.

8 0
3 years ago
What is the measure of ∠x?
Archy [21]

Answer:

114 degrees

Step-by-step explanation:

Hi there.

Line segment LN is a straight line, meaning that it contains a straight angle (an angle measuring 180 degrees).

We know that if this is a straight angle, that x+66=180.

Therefore, m∠x = 114 degrees.

Hope this helps! :^)

5 0
3 years ago
What is 5 + 2<br> ?<br> 51/2 + 21/7
Ghella [55]
Well 5+2 is 7 and 51/2+21/7 is 57/2
8 0
3 years ago
Read 2 more answers
(K3+2k2-82k-28)/(k+10)
Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

  • -10 | 1 + 2 - 82 - 28
  • ---------------------------

Now firstly, drop the 1:

  • -10 | 1 + 2 - 82 - 28
  •       ↓
  • -------------------------
  •        1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

  • -10 | 1 + 2 - 82 - 28
  •       ↓ - 10
  • -------------------------
  •        1 - 8

Next, multiply -10 and -8, then combine the product with -82:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80
  • -------------------------
  •        1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80 + 20
  • -------------------------
  •        1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is k^2-8k-2-\frac{8}{k+10}</u>

8 0
3 years ago
Which number between 17/4and 20
Talja [164]
Answer : 4.485
I’m pretty sure I just went with someone else answer !
8 0
3 years ago
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