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1 answer:
Answer:
New line =3*ZX
Step-by-step explanation:
It is given that the isosceles trapezoid is dilated using a scale factor of 1/3
and a line is drawn through the center of the new dilated figure, so
let us suppose that line is EF which is drawn and it will also pass through
the center in similar way the line ZX passes through so after considering this situation, we can come to this point
so new line will be 3 times longer than ZX.
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Step-by-step explanation:
The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45
∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120
∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:
5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:
Answer:
12
Step-by-step explanation:
The equation of circle in standard form is
Given that circle having center point (3,7) and the radius r = 4
To find: equation of circle in standard form
<em><u>The equation of circle is given as:</u></em>
Where center (h,k) and radius r units
Given that center point (h , k) = (3, 7) and radius r = 4 units
Substituting the values in above equation of circle,
Thus the equation of circle in standard form is