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Oksana_A [137]
3 years ago
8

A triangle drawn on a map has sides of lengths 8 centimeters,12 centimeters, and 14 centimeters.the shortest of the correspondin

g real-life distances is138 kilometers. find the longest of thereal-life distances.
Mathematics
1 answer:
borishaifa [10]3 years ago
3 0
241.5 kilometers, you have to divide to find the ratio (1:7.25) and multiply with the longest side
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Answer: -2/5

Step-by-step explanation:

To find the slope, we set the function use y = mx + b forms.

2x + 5y = 10

        5y = -2x + 10              Minus 2x in both side

           y = -2/5x + 10/5       Divide 5 from both side

           y = -2/5x + 2

In the y = mx + b, the m before variable x is always the slope, so -2/5 is the slope for 2x + 5y = 10.

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In order from least to greatest is 8.7, 8.83, 26/3, 79
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3 years ago
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Please help The perimeter of a rectangular shape electronic keyboard is 14 ft. Its width is 3 ft longer than its depth
kipiarov [429]

Answer:

Width = 6ft Area = 54 sq ft

Step-by-step explanation:

First, re-read the problem until you understand it and can put it into your own words.  I re-wrote it like this:  "Find the area of a rectangle by first finding the length (L) and the width (W)."   [note that I added "find L and W," but that is how I'm going to solve the problem;  I could also have said that we will need the formulas, P=2L+2W and A=LW, but you knew that already, right?).

 

Translate the problem:

 "The length of a rectangle is 3 ft longer than its width"      means

         L                             =    3             +         W                 (eq1)

 "the perimeter of the rectangle is 30 ft"     means

            P                                = 30                      (eq2)

 

So, now the math is easy, just find L and W so we can compute the area:

     P = 30 = 2L + 2W                         (eq3; from eq2 and the formula for P)

          30 = 2(3+W)  +  2W              (use eq1 to substitute for L)

          30 = 6 + 2W   + 2W              (distribute)

           30 = 6 + 4W                       (collect terms)

            24 = 4W                        (subtract 6 from both sides)

            6 ft = W                         (divide both sides by 4)

 

Use the easiest equation (either eq1 or else eq3) to find L:

          L = 3 + W        (eq1)

          L = 3 + 6

          L = 9 ft

What is the area (A)?

          A = L*W

          A = (9 ft)*(6 ft)

          A = 54 sq ft

3 0
2 years ago
En un pueblo hay tres iglesias cuyas campanas tocan cada 15 minutos, cada 20 minutos y cada 35 minutos. Suponiendo que en este i
34kurt

Answer:

420 minutos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encontramos los múltiplos de 15, 20 y 35

Múltiplos de 15:

15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375, 390, 405, 420, 435, 450

Múltiplos de 20:

20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240, 260, 280, 300, 320, 340, 360, 380, 400, 420, 440, 460

Múltiplos de 35:

35, 70, 105, 140, 175, 210, 245, 280, 315, 350, 385, 420, 455, 490

Por lo tanto,

MCM (15, 20, 35) = 420

El primer múltiplo común es el mínimo común múltiplo.

Por tanto, el tiempo en el que las 3 campanas de la iglesia volverán a coincidir = 420 minutos

7 0
2 years ago
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