A triangular prism<span> has 5 faces, 3 being rectangular and 2 being </span>triangular<span>. The </span>area<span> of the rectangular faces can be found by multiply the base and height lengths together. The </span>area<span> of the </span>triangular<span> faces can be found by multiplying the base and height and dividing by 2.</span>
Nine and a half times.
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you can put it fully nine times. You reach 18 like this. But you have 1 more to go until 19! So, just cut the 2 in half to get 1, and put that in!
If A=w(50-w)
A=50w-w^2
dA/dw=50-2w
d2A/dw2=-2
Since the acceleration is a constant negative, that means that when velocity, dA/dw=0, it is at an absolute maximum for A(w)...
dA/d2=0 only when 50=2w, w=25
So as the case with any rectangle, the perfect square will enclose the greatest area possible with respect to a given amount of material to enclose that area...
So the greatest area occurs when W=L=25 in this case:
A(25)=50w-w^2
Area maximum is thus:
Amax=50(25)-(25)^2=625 u^2
The equation of hyperbola can vary much from simple to complex equation. Since the information given from this question is not many, the equation probably was the simple one.
Assuming that the hyperbola formula is y= x^2 +b, then the value of b where x=-2 and y=-3 would be:
y= x^2 +b
-3= (-2)^2 +b
-3= 4+b
b=-3 -4= -7
The equation would be: y= x^2 -7
