Answer:
B. -7j-k-1
Step-by-step explanation:
Simplify:
1. IDENTIFY LIKE TERMS
<em>10k</em>+17-7j-18-<em>11k</em>
- <em>10k and -11k are like terms since they have the same variable.</em>
- 17 and -18 are like terms since they are regular numbers.
2. COMBINE LIKE TERMS
-7j-<em>k</em>-1
1/4 = 3/12, and 5/4 = 15/12, so it looks like there's a common difference between terms of 4/12 = 1/3. The the
-th term in the sequence is given recursively by

By substitution, we get


and doing this again and again until we stop with an expression containing
, we find that


Then the 12th term in the sequence is

For the 2nd picture, c. 26/7