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madreJ [45]
3 years ago
6

Help please! the question is in the picture below for reference when answering! thank you so much!

Mathematics
2 answers:
victus00 [196]3 years ago
7 0

Answer:

x = -1

Step-by-step explanation:

5x + 2x + 10 + 25 = 28

7x + 35 = 28

7x = -7

x = -1

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

stepan [7]3 years ago
4 0

Answer:

x = -1

Step-by-step explanation:

AB + BC = AC = 28

the way from A to C goes through B.

so, the total way of A to C is the sum of the way from A to B and then from B to C.

=>

(5x + 10) + (2x + 25) = 28

7x + 35 = 28

7x = -7

x = -1

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3 years ago
Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x 4 6x 3y =
wariber [46]

The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

\rm y = -2x+4 ....(1)\\  \\\rm 6x+3y= ?  ....(2)

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

\rm y = -2x+4 \\\\\rm 2x+y=4(multiply both the sides by 3)

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By comparing the equation (2) and (3), we get

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Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.

Learn more about the linear equation.

brainly.com/question/11897796

8 0
2 years ago
PLEASE HELP ASAP. Don’t send a link just put the answer. I’ll give brainpower to whoever answers!!!!!
givi [52]

Answer:

d/c = 8

Step-by-step explanation:

f(x) = 5.4321×2^×

f(4) = 5.4321×2^4 = d

f(1) = 5.4321×2^1 = c

d/c = (5.4321×2^4)/(5.4321×2^1) = 2^3 = 8

6 0
2 years ago
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